conic section
Question no. 16
P is any point on the ellipse 9x2 + 36y2 = 324, whose foci are S and S' . Then SP + S'P equals
looks_one 3
looks_two 12
looks_3 36
looks_4 324
Option looks_two 12
solution :
9x2 + 36y2 = 324
x2/36 + y2/16 = 1
SP + S'P = 2a = 2*6 = 12
9x2 + 36y2 = 324
x2/36 + y2/16 = 1
SP + S'P = 2a = 2*6 = 12
Question no. 17
The equation of the ellipse whose vertices are (∓5,0) and foci at (∓4, 0) is
looks_one x2/25 + y2/9 =1
looks_two x2/9 + y2/25 =1
looks_3 x2/16 + y2/25 =1
looks_4 x2/25 + y2/16 =1
option looks_one x2/25 + y2/9 =1
solutw2ion :
a= 5
ae = 4
e = 4/5
e2 = 1-b2/a2
16/25 = 1-b2/25
b = 3
the equation of ellipse , x2/25 + y2/9 =1
a= 5
ae = 4
e = 4/5
e2 = 1-b2/a2
16/25 = 1-b2/25
b = 3
the equation of ellipse , x2/25 + y2/9 =1
Question no. 18
The difference of focal distances of any point on hyperbola is equal to
looks_one latus rectum
looks_two semi-transverse axis
looks_3 transverse axis
looks_4 semi-latus rectum
option looks_3 transverse axis
Solution :
The difference of focal distances of any point on hyperbola is equal to transverse axis
The difference of focal distances of any point on hyperbola is equal to transverse axis
Question no. 19
The equation x2 -16xy -11y2 -12x +6y +21=0 represents
looks_one parabola
looks_two ellipse
looks_3 hyperbola
looks_4 two straight lines
option looks_3 hyperbola
Solution :
h= -8 ⇒ h2 = 64
a= 1
b = -11
h2 > ab and abc + 2fgh - af2 - bg2 - ch2 ≠ 0
therefore it is hyperbola
h= -8 ⇒ h2 = 64
a= 1
b = -11
h2 > ab and abc + 2fgh - af2 - bg2 - ch2 ≠ 0
therefore it is hyperbola
Question no. 20
The equation of the hyberbola whose directrix is 2x+y =1 , focus (1,1) and eccentricity = √3 , is
looks_one 7x2 +12xy -2y2 -2x + 4y -7 =0
looks_two 11x2 +12xy +2y2 -10x - 4y +1 =0
looks_3 11x2 +12xy +2y2 -14x - 14y +1 =0
looks_4 none of these
option looks_one 7x2 +12xy -2y2 -2x + 4y -7 =0
solution :
SP/SQ = e
5(x2 +1 -2x + y2 +1 - 2y) = 3 (4x2 + y2 +1 - 4x - 2y + 4xy )
7x2 +12xy -2y2 -2x + 4y -7 =0
SP/SQ = e
5(x2 +1 -2x + y2 +1 - 2y) = 3 (4x2 + y2 +1 - 4x - 2y + 4xy )
7x2 +12xy -2y2 -2x + 4y -7 =0
Question no. 21
x2 -4y2 -2x +16y + 40 = 0 represents
looks_one a pair of straight lines
looks_two ellipse
looks_3 hyperbola
looks_4 parabola
option looks_3 hyperbola
Solution :
abc + 2fgh - af2 - bg2 - ch2 ≠ 0
h2 > ab
therefore , it is hyperbola
abc + 2fgh - af2 - bg2 - ch2 ≠ 0
h2 > ab
therefore , it is hyperbola
Question no. 22
The distance between the directrices of the hyperbola x = 8secθ and y= 8tanθ
looks_one 16√2
looks_two √2
looks_3 8√2
looks_4 4√2
option looks_3 8√2
Solution :
x = asecθ and y = btanθ
a = 8 , b = 8
e2= 1 + a2/b2
e = √2
x = a/e = 8/√2
the distance between directrices = 2 *8/√2 = 8/√2
x = asecθ and y = btanθ
a = 8 , b = 8
e2= 1 + a2/b2
e = √2
x = a/e = 8/√2
the distance between directrices = 2 *8/√2 = 8/√2
Question no. 23
The eccentricity of the hyperbola 5x2 - 4y2 +20x +8y - 4=0 is
looks_one √2
looks_two 3/2
looks_3 2
looks_4 3
option looks_two 3/2
Solution :
5x2 - 4y2 +20x +8y - 4=0 , this equation can be written as
(x+2)2/4 - (y-1)2/5 = 1
5x2 - 4y2 +20x +8y - 4=0 , this equation can be written as
(x+2)2/4 - (y-1)2/5 = 1
Question no. 24
Consider the parabola S1 = y2 - 4ax =0 , and S2 = y2 - 4bx=0 . S2 will contain S1 , If
looks_one a > b > 0
looks_two b > a > 0
looks_3 a >0 , b<0 but |b|>a
looks_4 a <0 , b> 0 but b > |a|
option looks_two b > a > 0
Solution :
S1 = y2 - 4ax =0
S2 = y2 - 4bx=0 . S2 will contain S1
a > 0 , b> 0
latus rectum of S2 will always greater than S1 , therefore 4b > 4a
b > a
S1 = y2 - 4ax =0
S2 = y2 - 4bx=0 . S2 will contain S1
a > 0 , b> 0
latus rectum of S2 will always greater than S1 , therefore 4b > 4a
b > a
Question no. 25
What the sum of focal radii of any point on an ellipse equal to?
looks_one length of latus rectum
looks_two length of major axis
looks_3 length of minor axis
looks_4 length of semi latus rectum
option looks_two length of major axis
Sum of focal radii of any point on an ellipse equal to is length of major axis
Question no. 26
What is the locus of points , the difference of whose distances from two points being constant?
looks_one hyperbola
looks_two ellipse
looks_3 parabola
looks_4 pair of straight lines
option looks_one hyperbola
the locus of points when the difference of whose distances from two points being constant is hyperbola
Question no. 27
What are the equations of the directrices of the ellipse 25x2 + 16y2 =400?
looks_one 3x ∓ 25= 0
looks_two x ∓ 15=0
looks_3 3y ∓ 25= 0
looks_4 y ∓ 25= 0
option looks_3 3y ∓ 25= 0
Soltion :
25x2 + 16y2 =400
x2/16 + y2/25 =1
a<b : so equation of directrix is y = ∓b/e
e = 3/5
y = ∓b/e
y = ∓25/3
3y ∓ 25= 0
25x2 + 16y2 =400
x2/16 + y2/25 =1
a<b : so equation of directrix is y = ∓b/e
e = 3/5
y = ∓b/e
y = ∓25/3
3y ∓ 25= 0
Question no. 28
Let E be the ellipse x2/9 + y2/4 = 1 and C be the circle x2 + y2 =9 . Let P (1,2) and Q (2,1) . Which one of the following is correct?
looks_one Q lies inside C but outside E
looks_two Q lies outside both C and E
looks_3 P lies inside both C and E
looks_4 P lies inside C but outside E
option looks_4 P lies inside C but outside E
solution :
Point P (1,2) :
circle : x2 + y2 =9
12 + 22 = 5 < 9 , so point is inside the circle
ellipse : x2/9 + y2/4 = 1
12/9 + 22/4 = 10/9 > 1 , so point is outside the ellipse
Point P (2,1) :
circle : x2 + y2 =9
22 + 12 = 5 < 9 , so point is inside the circle
ellipse : x2/9 + y2/4 = 1
22/9 + 12/4 = 25/36 < 1 , so point is inside the ellipse
Point P (1,2) :
circle : x2 + y2 =9
12 + 22 = 5 < 9 , so point is inside the circle
ellipse : x2/9 + y2/4 = 1
12/9 + 22/4 = 10/9 > 1 , so point is outside the ellipse
Point P (2,1) :
circle : x2 + y2 =9
22 + 12 = 5 < 9 , so point is inside the circle
ellipse : x2/9 + y2/4 = 1
22/9 + 12/4 = 25/36 < 1 , so point is inside the ellipse
Question no. 29
A point moves such that difference of its distances from two given points (c,0) and (-c,0) is constant. What is the locus of the point P?
looks_one circle
looks_two ellipse
looks_3 hyperbola
looks_4 parabola
option looks_3 hyperbola
Solution :
the locus of point is hyperbola
the locus of point is hyperbola
Question no. 30
The curve y2= -4ax (a>0) lies in
looks_one first and fourth quadrants
looks_two first and second quadrants
looks_3 second and third quadrants
looks_4 third and fourth quadrants
option looks_3 second and third quadrants
solution :
second and third quadrants
second and third quadrants
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