Inverse Trigonometry Question no. 1 The Value of 1+ cot 2 (sin -1 x) looks_one 1/2x looks_two 2/x looks_3 x 2 looks_4 1/x 2 Answer Option looks_4 1/x 2 Solution Solution : 1+ cot 2 (sin -1 x) = cosec 2 (sin -1 x) = [cosec(cosec -1 (1/x))] 2 = [1/x] 2 = 1/x 2 Question no. 2 = looks_one tan -1 x looks_two looks_3 2tan -1 x looks_4 none of these Answer Option looks_two 1/2(tan -1 x) Solution Solution : Question no. 3 cos(tan -1 x)= looks_one looks_two looks_3 1+x 2 looks_4 none of these Answer Option looks_two Solution Solution : Question no. 4 = looks_one looks_two looks_3 looks_4 Answer Option Solution Solution : Question no. 5 = looks_one 1/x looks_two x looks_3 looks_4 Answer Option looks_two x Solution Solution : Question no. 6 sec 2 (tan -1 2)+cosec 2 (cot -1 3)= looks_one 5 loo...