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Complex Number | free study material for IIT-JEE , NDA and Airforce


Complex Number

⚫What is Complex number ?
⚪ Combination form of real and imaginary number
z = a + ib where i(iota) = √-1
⚫ Integer power of i (√-1)
(a) i4n = 1
(b) i4n+1 = i
(c) i4n+2 = -1
(d) i4n+3 = -i

⚫ Equality of two complex numbers
⚪ Two complex number z1 = x1 + iy1 and z2 = x2 + iy2 are said to be equal if and only if their real and imaginary parts are separately equal.
z1 = z2 ⇔ x1 + iy1 = x2 + iy2 ⇔ x1 = x2 and y1 = y2

⚫ Conjugate of a complex number :
⚪ For any complex number z = a + ib , then its conjugate is defined as z = a - ib
⚪ Geometrically , the conjugate of z is the reflection or point image of z in the real axis.

Properties of conjugate :
⚪   z̿ = z






⚪ z + z̅ = 2Re(z) = purely real
⚪ z - z̅ = 2iIm(z) = purely imaginary
⚪ zz̅ = |z|2 = purely real


Modulus of a complex number
⚪ Modulus of a complex number z = x+ iy is defined as the distance of the point (x,y) from the origin.

Properties of modulus
|z| = |z| = |-z| = |-z| =|zi|
zz = |z|2 = |z|2
|z1z2| = |z1||z2|
|z1z2z3......zn| = |z1||z2|.....|zn|
|zn| =|z|n
|z1 ± z2 |2 = |z1|2 + |z2|2 ± (z1z2 + z2z1 ) = |z1|2 + |z2|2 ± 2Re(z1z2)
|z1 + z2 |2 = |z1|2 + |z2|2 ⇒ z1/z2 is purely imaginary
|z1 + z2 |2 + |z1 - z2 |2 = 2 { |z1|2 + |z2|2 }

Argument of a complex number
⚪ Let z = a + ib be any complex number. If this complex number is represented geometricaaly by a point P , then the angle made by the OP with real axis is known as argument or amplitude of z.

De Moivre's Theorem
⚪ If n is any rational number , then ( cosθ + isinθ )n = cos nθ + isin nθ ⚪ If z =r(cosθ + i sinθ) and n is a positive integer , then
Triangle inequalities
⚪ In any triangle , sum of any two sides is greater than the third side and the difference of any two side is less than the third side.
⚪ |z1 + z2| ≤ |z1| + |z2|
⚪ |z1 - z2| ≤ |z1| + |z2|
⚪ |z1 + z2| ≥ | |z1| - |z2| |
⚪ |z1 - z2| ≥ | |z1| - |z2| |

Roots of a Complex Number
nth roots of complex number
Let z = r (cos θ + i sin θ) be a complex number . By using De ' moivre 's theorem nth roots having n distinct values of a complex numbers
The nth roots of unity xn = 1 = cos 0o + i sin 0o = cos 2kπ + i sin 2kπ
x = [cos 2kπ + i sin 2kπ]1/n
Using De Moivre's Theorem

⚫ Properties of nth roots of unity
⚪ The sum of all n roots of unity is zero
        1 + a + a2 + ..... + an-1 = 0
⚪ Product of all n roots of unity is (-1)n-1

Cube roots of unity
x3 - 1 = 0 ⇒ x = (1)1/3
Properties of cube roots of unity
⚫ 1 + ω + ω2 = 0
⚫ ω3 = 1
⚫ 1 + ωn + ω2n = 0 { if n is not a multiple of 3 }
⚫ 1 + ωn + ω2n = 3 { if n is a multiple of 3 }

Video lectures for complex number :

NDA Maths Lecture 1 :

NDA Maths Lecture 2 :

NDA Maths Lecture 3 :

NDA Maths Lecture 4 :

NDA Maths Lecture 5 :

NDA Maths Lecture 6 :


Assignment Practice set 1 Practice set 2 Practice set 3

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