Practice Question On Matrix and determinant | CBSE | IITJEE | MAINS | ADVANCED | NDA | AIRFORCE | 31-45
Matrix and determinant
Question no. 31
If A=
, then A100 =
looks_one 2100A
looks_two299A
looks_3 2101A
looks_4 None of these
Option looks_two299A
Solution :
Characteristic eqaution :
(1- λ)2 - 1 = 0
λ2 + 1 - 2λ - 1 = 0
λ2 - 2λ = 0
A2 = 2A
A3 = 2A2 = 22A
A4 = 2A3 = 23 A
.
.
.
.
A100 = 299A
Characteristic eqaution :
(1- λ)2 - 1 = 0
λ2 + 1 - 2λ - 1 = 0
λ2 - 2λ = 0
A2 = 2A
A3 = 2A2 = 22A
A4 = 2A3 = 23 A
.
.
.
.
A100 = 299A
Question no. 32
Matrix A=
is invertible for
looks_one k=1
looks_two k=0
looks_3 k=-1
looks_4 All real k
option looks_two k=0
Solution :
For Invertible , |A| ≠ 0
1(1) - k(k) ≠ 0
k2 ≠ 1
K ≠ 1 , -1
For Invertible , |A| ≠ 0
1(1) - k(k) ≠ 0
k2 ≠ 1
K ≠ 1 , -1
Question no. 33
If
, then values of x,y,z,w are
looks_one 2,2,3,4
looks_two 2,3,1,2
looks_3 3,3,0,1
looks_4 None of these
option looks_one 2,2,3,4
Solution :
x+ y = 4 .....[1]
x- y = 0 .......[2]
Solve [1] and [2]
x = 2 , y = 2
2x + z = 7 ⇒ 4 + z = 7 ⇒ z = 3
2z + w = 10 ⇒ 6 + w = 10
w = 4
x+ y = 4 .....[1]
x- y = 0 .......[2]
Solve [1] and [2]
x = 2 , y = 2
2x + z = 7 ⇒ 4 + z = 7 ⇒ z = 3
2z + w = 10 ⇒ 6 + w = 10
w = 4
Question no. 34
If A and B are 3✕3 matrices such that AB=A and BA=B, then
looks_one A2=A and B2 ≠ B
looks_two A2 ≠ A and B2 = B
looks_3 A2 = A and B2 = B
looks_4 A2 ≠ A and B2 ≠ B
option looks_3 A2 = A and B2 = B
Solution :
Case 1 :
AB = A
A(BA) = A
ABA = A
(AB)A = A
AA = A
A2 = A
Case 2 :
BA = B
B(AB) = B
BB = B
B2 = B
Case 1 :
AB = A
A(BA) = A
ABA = A
(AB)A = A
AA = A
A2 = A
Case 2 :
BA = B
B(AB) = B
BB = B
B2 = B
Question no. 35
If I is unit matrix , then 3I will be
looks_one A unit matrix
looks_two A triangular matrix
looks_3 A scalar matrix
looks_4 None of these
option looks_3 A scalar matrix
Solution :
I is identity matrix
whereas 3I will be scalar matrix
I is identity matrix
whereas 3I will be scalar matrix
Question no. 36
If A=
, then A2 - 5A =
looks_one I
looks_two 14I
looks_3 0
looks_4 None of these
option looks_two 14I
Solution :
Question no. 37
If
then A4 =
looks_one 
looks_two 
looks_3 
looks_4 
option looks_one
Solution :


Question no. 38
If
, then
looks_one AB = O, BA = O
looks_two AB = O, BA ≠ O
looks_3 AB ≠ O, BA = O
looks_4 AB ≠ O, BA ≠ O
Option looks_one AB = O, BA = O
Solution :
|A| = 0
|B| = 0
then
AB = 0
BA = 0
|A| = 0
|B| = 0
then
AB = 0
BA = 0
Question no. 39
Choose the correct answer
looks_one Every identity matrix is a scalar matrix
looks_two Every scalar matrix is an identity matrix
looks_3 Every diagonal matrix is an identity matrix
looks_4 A square matrix whose each element is 1 is identity matrix
option looks_one Every identity matrix is a scalar matrix
Solution :
Every identity matrix is a scalar matrix
Every identity matrix is a scalar matrix
Question no. 40
If A and B are square matrices of order n ✕ n , then matrices ( A -B )2 is equal to
looks_one A2 - B2
looks_two A2 -2AB + B2
looks_3 A2 +2AB + B2
looks_4 A2 -AB -BA + B2
Option looks_4 A2 -AB -BA + B2
Solution :
( A -B )2 = (A-B)(A-B)
(A-B)(A-B) = A2 -AB -BA + B2
( A -B )2 = (A-B)(A-B)
(A-B)(A-B) = A2 -AB -BA + B2
Question no. 41
If
then VU +X'Y =
looks_one 20
looks_two [20]
looks_3 [-20]
looks_4 -20
Option looks_two [20]
Solution :
Question no. 42
Which one of the following is not true
looks_one Matrix addition is commutative
looks_two Matrix addition is associative
looks_3 Matrix multiplication is commutative
looks_4 Matrix multiplication is associative
Option looks_3 Matrix multiplication is commutative
Solution :
Matrix multiplication is not commutative
Matrix multiplication is not commutative
Question no. 43
If
, then
, then
looks_one A2 = A
looks_two B2 = B
looks_3 AB ≠ BA
looks_4 AB = BA
option looks_3 AB ≠ BA
Solution :
AB ≠ BA
AB ≠ BA
Question no. 44
Which of the following is incorrect?
looks_one A2 -B2 = (A+B)(A-B)
looks_two (AT)T = A
looks_3 (AB)n= AnBn where A, B commute
looks_4 (A-I) (I+A) = O , that imply A2 = I
option looks_one A2 -B2 = (A+B)(A-B)
Solution :
(A+B)(A-B) = A2 + BA -AB -B2
BA ≠ AB
A2 -B2 ≠ (A+B)(A-B)
(A+B)(A-B) = A2 + BA -AB -B2
BA ≠ AB
A2 -B2 ≠ (A+B)(A-B)
Question no. 45
If
, then X =
, then X =
looks_one
looks_two
looks_3 
looks_4 
Option looks_one 
Solution :
AX = B
X = A-1B
AX = B
X = A-1B
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