Probability Question no. 16 The mean and variance of a binomial distribution are 4 and 3 respectively , then he probability of getting six successes in this distribution , is looks_one looks_two looks_3 looks_4 Answer Option looks_two Solution Solution : np = 4 ....[1] npq = 3 ....[2] divide [2] by [1] q = 3/4 p + q = 1 p = 1/4 n*(1/4) = 4 n = 16 P(six success) = 16 C 6 (1/4) 6 (3/4) 10 Question no. 17 A coin is tossed 10 time. The probability of getting exactly six heads is looks_one looks_two looks_3 looks_4 none of these Answer Option looks_two Solution Solution : n=10 p = q = 1/2 Probability of getting exactly six heads = 10 C 6 (1/2) 6 (1/2) 4 = 105/512 Question no. 18 A five digit number is written down at random. The probability that the number is divisible by 5 and no two consecutive digits are identical, is looks_one looks_two looks_3 looks_4 No...