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CBSE 10th Class Sample paper 1

General Instruction 1. All the questions are compulsory 2. The question paper consists of 40 question and it is divided into four sections A,B , C and D. SECTION A Comprises of 20 questions carrying 1 mark each. Section B comprises of 6 questions carrying 2 marks each, Second C comprises of 8 questions carrying 3 marks cach. Section D comprises of 6 questions carrying 4 marks each. 3. There is no overall choice 4. Use of calculator is not permitted. Section A 1. If p and q are co-prime, then p 2 and q 2 are ______________ 2. If ∆ABC∼∆DEF, BC=3cm, EF= 4cm and ar( ∆ABC) = 54 cm 2 , then ar(∆DEF) =..... 3. If 5tanθ-4 =0 , then the value of (5sinθ -4cosθ)/( 5sinθ+ 4cosθ) is...... 4. A die is thrown once. The probability of getting a prime number (A) 2/3 (B) 1/3 (C) 1/2 (D) 1/6 5. the equation x 2 + 4x + k= 0 has real and distinct roots. then (A) K (B) k>4 (C) k <= 4 (D) k>= 4 6. If the circumference and the area of a circle are numeri...

Practice question on height and distance for IIT JEE , Airforce and NDA 16-30 (SET 2 )

Height and distance Question no. 16 The angle of depression of a ship from the top of a tower 30 m high is 60 o , then the distance of ship from the base of tower is looks_one 30 m looks_two 30√ 3 m looks_3 10√ 3 m looks_4 10 m Answer Option looks_3 10√ 3 m Solution Solution : o , then the distance of ship from the base of tower is" border="0" width="250" data-original-height="235" data-original-width="347" src="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEggUqrnuJkswqvAGBSYPLs6FMLv7tUicziLxiJtl-artyBlR0W8aB-9jau9mJa1Tqn_4XVxzZuZkJh8OmI41u7puCsX6XSEt6euSEnnR_zObf98lbc-wAQePqOWwSyrZxEnIHzkq4pG1qE/s400/question16_heightanddistance.png"/> In given triangle tan 60 o = 30/x √ 3 = 30/x x = 30/√ 3 x = 10√ 3 Question no. 17 A tree is broken by wind , its upper part touches the ground at a point 10 meters from the foot of the tree and makes an angle...

Practice Question on Vector for IIT-JEE , NDA and Airforce 31-45 | SAT | CBSE | UPSC | IITJEE | NDA

Vector Question no. 31 If | a . b |=3 and | a ✕ b |=4 , then the angle between a and b is looks_one cos -1 (3/4) looks_two cos -1 (3/5) looks_3 cos -1 (4/5) looks_4 45 o Answer Option looks_two cos -1 (3/5) Solution Solution : | a . b |= | a || b |cosθ = 3 ......[1] | a ✕ b | = | a || b |sinθ = 4 ......[2] Divide [2] by [1] sinθ/cosθ = 4/3 tanθ = 4/3 θ = tan -1 (4/3) θ = cos -1 (3/5) Question no. 32 The Vector a = α i + 2 j +β k lies in the plane of the vectors b = i + j and c = j + k and bisects the angle between b and c . then the value of α and β looks_one 2 ,2 looks_two 1,1 looks_3 2,1 looks_4 1,2 Answer option looks_two 1,1 Solution Solution : a = α i + 2 j +β k a lies in the plane of the vectors b and c a .( b ✕ c ) = 0 Question no. 33 If [ a ✕ b    b...

Practice question on Vector for NDA , IIT-JEE , and Air force | NDA | IITJEE | CBSE | SAT | UPSC 16-30 (SET 2)

Vector Question no. 16 If a , b and c are three coplanar vector , then looks_one a .( b ✕ c )=1 looks_two a .( b ✕ c )= 3 looks_3 c .( a ✕ b )=0 looks_4 b .( c ✕ a )=1 Answer Option looks_3 c .( a ✕ b )=0 Solution Solution : If a , b and c are three coplanar vector c .( a ✕ b )=0 Question no. 17 Given a = i + j - k and b= - i + 2 j + k , c= - i + 2 j - k . A unit vector prependicular to both a + b and c + b looks_one i looks_two j looks_3 k looks_4 ( i + j + k )/√3 Answer Option looks_3 k Solution Solution : a = i + j - k b= - i + 2 j + k c= - i + 2 j - k a + b = 3 j c + b = -2 i + 4 j A unit vector prependicular to both a + b and c + b is cross product of both vector. Unit Vector = k Question no. 18 For any vector a and b ,if a ✕ b =0 and a . b =0 then looks_one a is parallel to...